table of contents
std::mdspan::operator[](3) | C++ Standard Libary | std::mdspan::operator[](3) |
NAME¶
std::mdspan::operator[] - std::mdspan::operator[]
Synopsis¶
template< class... OtherIndexTypes >
constexpr reference operator[]( OtherIndexTypes... indices ) (1)
(since C++23)
const;
template< class OtherIndexType >
constexpr reference operator[] (2) (since C++23)
( std::span<OtherIndexType, rank()> indices ) const;
template< class OtherIndexType >
constexpr reference operator[] (3) (since C++23)
( const std::array<OtherIndexType, rank()>& indices ) const;
Returns a reference to the indices^th element of the mdspan.
1) Equivalent to return acc_.access(ptr_,
map_(static_cast<index_type>(std::move(indices))...));.
This overload participates in overload resolution only if:
* (std::is_convertible_v<OtherIndexTypes, index_type> && ...)
is true,
* (std::is_nothrow_constructible_v<index_type, OtherIndexTypes>
&& ...) is true,
and
* sizeof...(OtherIndexTypes) == rank() is true.
Let I be extents_type::index-cast(std::move(indices)). Then the behavior is
undefined if I is not a multidimensional index in extents(), i.e., map_(I)
<
map_.required_span_size() is false.
2,3) Let P be a parameter pack such that
std::is_same_v<make_index_sequence<rank()>,
index_sequence<P...>> is true, then the operator is equivalent to
return
operator[](extents_type::index-cast(std::as_const(indices[P]))...);.
This overload participates in overload resolution only if:
* std::is_convertible_v<const OtherIndexType&, index_type> is true,
and
* std::is_nothrow_constructible_v<index_type, const
OtherIndexType&> is true.
Parameters¶
indices - the indices of the element to access
Return value¶
A reference to the element.
Example¶
This section is incomplete
Reason: no example
Defect reports
The following behavior-changing defect reports were applied retroactively to
previously published C++ standards.
DR Applied to Behavior as published Correct behavior
LWG 3974 C++23 overloads (2,3) did not apply applies
extents_type::index-cast
See also¶
This section is incomplete
Categories:¶
* Todo no example
* Todo without reason
2024.06.10 | http://cppreference.com |